7 Simple Steps to Balancing Redox Reactions

Cr2O72-+ 14H+ + 6e- → 2Cr3+ + 7H2O

This one’s a little tricky…

The overall charge of the reactants is +12, because of the 14H+ and the one Cr2O72-

The overall charge of the products is +6 because of the 2Cr3+

Therefore, we add 6 electrons to the reactants so that both sides are +6

Fe2+ → Fe3+ + e-

The reactants are +2 and the products are +3, so the products need one electron

Notice how this reaction has electrons as products and the first one has electrons as reactants

Click Here