Why Is [Ni(NH3)6]Cl2 Paramagnetic But [Co(NH3)6]Cl3 Is Diamagnetic ?
<p>In case of <a href="https://chemizi.blogspot.com/2020/04/outer-orbital-complexes-definition.html" rel="noopener ugc nofollow" target="_blank"><strong>[Ni(NH3)6]Cl2 complex</strong></a><strong>,</strong> the oxidation state of nickel atom is +2 .The atomic number of nickel atom, <strong>28 and that of Ni(II)ion is 26 .</strong></p>
<p>Valence shell electronic configuration of <a href="https://chemizi.blogspot.com/2020/04/outer-orbital-complexes-definition.html" rel="noopener ugc nofollow" target="_blank"><strong>Ni(II) ion is [ Ar ] d8</strong></a><strong> </strong>. <strong>Coordination </strong>number of central metal <strong>Ni(II)ion : 6 . </strong>Arrangement of <strong>[Ni(NH3)6]Cl2 complex is Octahedral</strong>.</p>
<p>Now, the <strong>paramagnetic</strong> character of above said octahedral <strong>Ni(II) </strong>complex does not explained on the basis of <a href="https://chemizi.blogspot.com/2020/04/outer-orbital-complexes-definition.html" rel="noopener ugc nofollow" target="_blank"><strong>crystal field theory</strong></a>.</p>
<p>Because, the ligand <strong>NH3 </strong>is a strong field ligand. So, <strong>under the influence</strong> of the octahedral crystal field, the five degenerate d-orbitals of <strong>Ni(II)</strong> ion are splitted into <strong>two sets of energetically different orbitals</strong>.</p>
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